% Compute butterworth filter order and cutoff for the desired response % characteristics. Rp is the allowable decibels of ripple in the pass % band. Rs is the minimum attenuation in the stop band. % % [n, Wc] = buttord(Wp, Ws, Rp, Rs) % Low pass (Wp<Ws) or high pass (Wp>Ws) filter design. Wp is the % pass band edge and Ws is the stop band edge. Frequencies are % normalized to [0,1], corresponding to the range [0,Fs/2]. % % [n, Wc] = buttord([Wp1, Wp2], [Ws1, Ws2], Rp, Rs) % Band pass (Ws1<Wp1<Wp2<Ws2) or band reject (Wp1<Ws1<Ws2<Wp2) % filter design. Wp gives the edges of the pass band, and Ws gives % the edges of the stop band. % % Theory: |H(W)|^2 = 1/[1+(W/Wc)^(2N)] = 10^(-R/10) % With some algebra, you can solve simultaneously for Wc and N given % Ws,Rs and Wp,Rp. For high pass filters, subtracting the band edges % from Fs/2, performing the test, and swapping the resulting Wc back % works beautifully. For bandpass and bandstop filters this process % significantly overdesigns. Artificially dividing N by 2 in this case % helps a lot, but it still overdesigns. % % See also: butter

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